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如何點擊a標簽實現彈出input file上傳文件對話框
編輯:HTML和Xhtml     
html

復制代碼代碼如下:
<SPAN class=tag><<SPAN class=title>div</SPAN>></SPAN>
<SPAN class=tag><<SPAN class=title>a</SPAN> <SPAN class=attribute>href</SPAN>=<SPAN class=value>"###"</SPAN>></SPAN>添加圖片<SPAN class=tag></<SPAN class=title>a</SPAN>></SPAN>
<SPAN class=tag><<SPAN class=title>input</SPAN> <SPAN class=attribute>type</SPAN>=<SPAN class=value>"file"</SPAN> <SPAN class=attribute>name</SPAN>=<SPAN class=value>"image"</SPAN> <SPAN class=attribute>class</SPAN>=<SPAN class=value>"hidden"</SPAN> <SPAN class=attribute>value</SPAN>=<SPAN class=value>""</SPAN> /></SPAN>
<SPAN class=tag></<SPAN class=title>div</SPAN>></SPAN>

css

復制代碼代碼如下:
<SPAN class=class>.hidden</SPAN> <SPAN class=rules>{
<SPAN class=rule><SPAN class=attribute>display</SPAN>:<SPAN class=value> none;</SPAN></SPAN>
<SPAN class=rule>}</SPAN></SPAN>


復制代碼代碼如下:
jquery
$('a').on('click', function(e) {
e.preventDefault();
$(this).closest('input[type=file]').trigger('click');
})
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