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javascript 節點排序 2
編輯:關於JavaScript     
復制代碼 代碼如下:
//靈感來自
//http://www.cnblogs.com/jkisjk/archive/2011/01/28/array_quickly_sortby.html
var hasDuplicate = false;
var sortBy = function(nodes){
var result = [], array = [], n = nodes.length, i = n, node;
while(node = nodes[--n]){
(array[n] = new Number(~~node.sourceIndex))._ = node;
}
array.sort(function(a,b){
if(a === b) hasDuplicate = true;
return a - b ;
});
while( i )
result[--i] = array[i]._;
return result;
}

但標准浏覽器不支持這屬性,在IE中,XML文檔也沒有此屬性,這時就需要跟據節點的parentNode與nextSibling,但如果單單是兩兩比較,速度是提升不了的。因此我們就轉而比較最近公共祖先的孩子們的順序了。這時,算法的威力就體現出來了。這是第一版,根據某一朋友提供的LCA搞出來的東西,當然大體思路還是歸功於JK大神。但實際效果不如意,比jQuery的那個sortOrder慢,估計問題出在求LCA上。
復制代碼 代碼如下:
//根據這裡JK提供的思路
//http://www.cnblogs.com/rubylouvre/archive/2011/01/28/1947286.html#2020900
var tick = 0, hasDuplicate = false;
var Rage = {
//form http://www.cnblogs.com/GrayZhang/archive/2010/12/29/find-closest-common-parent.html
getLCA:function(nodes){
var hash = {}, i = 0,
attr = "data-find"+(++tick),
length = nodes.length,
node,
parent,
counter = 0,
uuid;
while(node = nodes[i++]){
parent = node;
while(parent){
if(parent.nodeType === 1){
break;
}
uuid = parent.getAttribute(attr);
if(!uuid){
uuid = "_" + (++counter);
parent.setAttribute(attr,uuid);
hash[uuid] = {node:parent,count:1};
}else{
hash[uuid].count ++;
}
parent = parent.parentNode;
}
}
for(var i in hash){
if(hash[i].count === length){
return hash[i].node;
}
}
},
getList : function(nodes,parent){//獲取當前元素到最近公共祖先間的所有祖先,包括自己
var list = [];
while(node){
if(node === parent){
break;
}
list.unshift(node);
node = node.parentNode;
}
return list;
},
getLists : function(){
var lists = [], getList = Rage.getList, i=0, node, list;
while(node = nodes[i++]){
list = getList(node,parent);
if(list.length){
lists[ lists.length ] = list;
}
}
return lists;
},
sortList : function(a,b){
var n = Math.min(a.length,b.length),ap,bp;
for(var i=0; i < n; i++){
ap = a[i],bp = b[i]
if(ap !== bp){
while(ap = ap.nextSibling){
if(ap === bp){
return -1
}
}
return 1
}
}
return a.length-b.length;
},
uniqueSort : function(nodes){
var length = nodes.length;
var LCA = Rage.getLCA(nodes);
var lists = Rage.getLists(nodes,LCA);
lists.sort(Rage.sortList);
var list, i = 0, result = [];
while(list = lists[i++]){
result[result.length] list.pop();
}
if(result.length !== length){
result.unshift(LAC);
if(result.length != length){
hasDuplicate = true;
}
}
return result;
}
}

下面是第二版,經過改進,終於比jQuery的那個快上三倍(測試對象為擁有260多個節點的文檔)
復制代碼 代碼如下:
var hasDuplicate = false;
var Rage = {
getList : function(node){
var list = [];
while(node){
if(node.nodeType === 9){
break;
}
list.unshift(node);
node = node.parentNode;
}
return list;
},
getLists : function(nodes){
var lists = [], getList = Rage.getList, i=0, node;
while(node = nodes[i++]){
lists[ lists.length ] = getList(node);
}
return lists;
},
sliceList : function(lists,num){
var result = [], i = 0, list;
while(list = lists[i++]){
list = list.slice(num);
if(list.length){
result[ result.length ] = list;
}
}
return result;
},
sortList : function(a,b){
var n = Math.min(a.length,b.length),ap,bp;
for(var i=0; i < n; i++){
ap = a[i],bp = b[i]
if(ap !== bp){
while(ap = ap.nextSibling){
if(ap === bp){
return -1
}
}
return 1
}
}
return a.length-b.length;
},
uniqueSort : function(nodes){
var length = nodes.length;
var lists = Rage.getLists(nodes);
lists.sort(function(a,b){
return a.length - b.length;
});
var depth = lists[0].length, length = lists.length, parent, cut, ii = 0;
for(var i =0; i < depth; i++){
parent = lists[0][i];
cut = true;
for(var j = 1;j < length; j++){
if(parent !== lists[j][i]){
cut = false;
break;
}
}
if(cut){
ii++
}else{
break;
}
}
var LCA = lists[0][ii-1];
lists = Rage.sliceList(lists,ii);
lists.sort(Rage.sortList);
var list, i = 0, result = [];
while(list = lists[i++]){
result[result.length] = list.pop();
}
if(result.length !== length){
result.unshift(LCA);
if(result.length != length){
hasDuplicate = true;
}
}
return result;
}
}
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