本文實例講述了JavaScript使用RegExp進行正則匹配的方法。分享給大家供大家參考。具體實現方法如下：
<script type="text/javascript">
var matchedTimes = 0;
//Match one d followed by one or more b's followed by one d
//Remember matched b's and the following d
//Ignore case
myRe = new RegExp("d(b+)(d)", "ig");
// 等價於 myReg = /d(b+)(d)/ig;
myArray = myRe.exec("ecDBDsdbbdz"); // ecdbBdbsdbbdz
console.log("Regular Expression String: " + myRe.source);
console.log("Is global? " + myRe.global);
console.log("Ignore case? " + myRe.ignoreCase);
console.log("Is mulitiline? " + myRe.multiline);
console.log("------------------------------------------------");
logInfo(myArray, myRe);
myArray = myRe.exec("ecDBDsdbbdz");
logInfo(myArray, myRe);
function logInfo(myArray, myRe) {
matchedTimes++;
console.log("This is " + matchedTimes + " times match");
console.log("Original String: " + myArray.input);
console.log("Match Result Array: [" + myArray + "]");
console.log("The 0-based index of the match in the string: " + myArray.index);
console.log("The last matched characters: " + myArray[0]);
console.log("The parenthesized substring matches [1]: " + myArray[1]);
console.log("The parenthesized substring matches [2]: " + myArray[2]);
console.log("The index at which to start the next match: " + myRe.lastIndex);
console.log("-----------------------------------------------");
}
myRe2 = /^\w+(\d*)$/ig
console.log("myRe2: " + myRe2.source);
//console.log("myRe2 matches abc1? " + myRe2.test("abc1"));
// 加上這行跑跑看結果，因為是global匹配，所以lastIndex會改變，
//所以後面的myRe2.test("abc")當然就是false
console.log("myRe2 matches abc? " + myRe2.test("abc"));
</script>
希望本文所述對大家的javascript程序設計有所幫助。